Let О”abcв€јо”def And Their Areas Be Respectively 64cmві And 121cmві. If Ef=15.4cm Find Bc. -

import math area_abc = 64 area_def = 121 ef = 15.4 # Ratio of areas of similar triangles is equal to the square of the ratio of their corresponding sides. # (BC / EF)^2 = Area(ABC) / Area(DEF) # BC / EF = sqrt(Area(ABC) / Area(DEF)) bc = ef * math.sqrt(area_abc / area_def) print(f"{bc=}") Use code with caution. Copied to clipboard

For two similar triangles, the ratio of their areas is equal to the square of the ratio of their corresponding sides. This relationship is expressed by the formula: import math area_abc = 64 area_def = 121 ef = 15

Area(△ABC)Area(△DEF)=(BCEF)2the fraction with numerator Area open paren triangle cap A cap B cap C close paren and denominator Area open paren triangle cap D cap E cap F close paren end-fraction equals open paren the fraction with numerator cap B cap C and denominator cap E cap F end-fraction close paren squared 2. Substitute the known values Plug the given areas ( ) and the length of side EFcap E cap F ) into the formula: Calculate the ratio of sides

811=BC15.48 over 11 end-fraction equals the fraction with numerator cap B cap C and denominator 15.4 end-fraction 4. Solve for side BCcap B cap C Multiply both sides by to isolate BCcap B cap C import math area_abc = 64 area_def = 121 ef = 15

BC=811×15.4cap B cap C equals 8 over 11 end-fraction cross 15.4 BC=8×1.4cap B cap C equals 8 cross 1.4 BC=11.2 cmcap B cap C equals 11.2 cm ✅ Final Answer The length of the corresponding side BCcap B cap C

64121=(BC15.4)264 over 121 end-fraction equals open paren the fraction with numerator cap B cap C and denominator 15.4 end-fraction close paren squared 3. Calculate the ratio of sides